Thursday, August 12, 2010

Questions 1,3 and 5

Q1.) The statement is true. { 'A square is a rhombus but a rhombus is not a square'. }


A square is a special kind of rhombus. In fact, a square is also a special kind of rectangle. Just like the rhombus which is a special kind of parallelogram, the rectangle is also a special kind of parallelogram thus the rhombus is also a special kind of parallelogram.


"A square is a special kind of rhombus." Why is this so?

This is because the square has 4 equal sides like the rhombus but the special feature of the square is that every angle in it is a right angle.


'A square is a rhombus but a rhombus is not a square'  [Proved]


Q3.)It is a trapezium.


A trapezium has only one pair of side which are parallel and the other two are not.




5.)If ABCD is a parallelogram, and if E is midpoint of AD and  F is midpoint of BC, BFDE must be a parallelogram. This is because BF and ED are equal and parallel.

3 comments:

  1. Done by Christopher John
    (Sorry I forgot to add in my name)

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  2. I like the point when you highlighted that a square is a special kind of rhombus. My question : why not a rhombus is a special kind of square? Are these two statements different? Is rhombus a special member of the square family?
    Think about this

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  3. A rhombus is not a square as it does not have a right angle in its all four angle

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